Can you take the derivative of a nonlinear equation; substitute it in for a variable m representing slope in an otherwise linear equation, and then get back the original nonlinear equation.
-
You mean the point-slope formula? No.
Try with y=sin(x)
dy/dx=cos(x)
m=cos(x)
point on y=sin(x):(0,0)
y-0=cos(x)(x-0)
y=xcos(x).
xcos(x)≠sin(x)
Try with y=sin(x)
dy/dx=cos(x)
m=cos(x)
point on y=sin(x):(0,0)
y-0=cos(x)(x-0)
y=xcos(x).
xcos(x)≠sin(x)