Please show me how you find these. Thank you in advance(:
-
csc = 1/sin
as sin(3/4pi) = 1/√2
csc(3/4pi) = √2
as sin(-2/3pi)=-sin(2/3pi) = -√3/2
csc(-2/3pi) = -2/√3 = - (2√3)/3
as sin(3/4pi) = 1/√2
csc(3/4pi) = √2
as sin(-2/3pi)=-sin(2/3pi) = -√3/2
csc(-2/3pi) = -2/√3 = - (2√3)/3
-
(3π/4) radians = 135º
(- 2π/3) radians = - 120 º
csc (θ) = 1/sin θ
Now you need to get the unit circle out...or special right triangles, with the correct quadrant !
@ƒ
[sin (π/4) = (√2) / 2, sin (π/3) = (√3)/2
those should help some !]
(- 2π/3) radians = - 120 º
csc (θ) = 1/sin θ
Now you need to get the unit circle out...or special right triangles, with the correct quadrant !
@ƒ
[sin (π/4) = (√2) / 2, sin (π/3) = (√3)/2
those should help some !]
-
(1) csc(pi - pi/4) = csc(pi/4) = sqrt(2) . (2) -csc(pi - pi/3) = -csc(pi/3) = -2/(sqrt3)