Not sure how someone simplified this problem?
√(64sin^(2)2t+36cos^(2)2t) = √(36+28sin^(2)2t) = 2√(9+7sin^(2)2t)
√(64sin^(2)2t+36cos^(2)2t) = √(36+28sin^(2)2t) = 2√(9+7sin^(2)2t)
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Ans.
√(64sin^(2)2t+36cos^(2)2t) =√(28 sin^2 2t + 36sin^(2)2t+36cos^(2)2t) = √(36+28sin^(2)2t) =
= √4(9+ 7 sin^(2)2t) =2√(9+7sin^(2)2t)
√(64sin^(2)2t+36cos^(2)2t) =√(28 sin^2 2t + 36sin^(2)2t+36cos^(2)2t) = √(36+28sin^(2)2t) =
= √4(9+ 7 sin^(2)2t) =2√(9+7sin^(2)2t)