Steps that show how to simplify this...√(64sin22t+36cos22t) = √(36+28sin22t) = 2√(9+7sin22t)
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HOME > > Steps that show how to simplify this...√(64sin22t+36cos22t) = √(36+28sin22t) = 2√(9+7sin22t)

Steps that show how to simplify this...√(64sin22t+36cos22t) = √(36+28sin22t) = 2√(9+7sin22t)

[From: ] [author: ] [Date: 12-11-20] [Hit: ]
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Not sure how someone simplified this problem?

√(64sin^(2)2t+36cos^(2)2t) = √(36+28sin^(2)2t) = 2√(9+7sin^(2)2t)

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Ans.

√(64sin^(2)2t+36cos^(2)2t) =√(28 sin^2 2t + 36sin^(2)2t+36cos^(2)2t) = √(36+28sin^(2)2t) =

= √4(9+ 7 sin^(2)2t) =2√(9+7sin^(2)2t)
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