Please show method..really need help
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Please show method..really need help

[From: ] [author: ] [Date: 12-07-14] [Hit: ]
a(t) = 1000e^0.a(4) = 1000e^2.7726 = 16,000 bacteria-the number of bacteria is increasing by 3000 per 2 hrs.........
The number of bacteria in a colony was growing exponentially. At 1 pm yesterday
the number of bacteria was 1000 and at 3 pm yesterday it was 4000. How many
bacteria were there in the colony at 5 pm yesterday?

-
a(t) = pe^rt where t = hours since 1 pm
p = a(0) = 1000
a(t) = 1000e^rt
a(2) = 4000 = 1000e^2r
e^2r = 4
2r = ln 4
r = 0.6931
a(t) = 1000e^0.6931t
a(4) = 1000e^2.7726 = 16,000 bacteria

-
the number of bacteria is increasing by 3000 per 2 hrs........

at 1pm => 1000
at 3pm=> 4000
so
after 2 hours ( that means at 5 pm)=> 4000+3000 =7000...........

i hope u understand
1
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