Brief calculus help please
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Brief calculus help please

[From: ] [author: ] [Date: 12-07-14] [Hit: ]
Which is: ( - 6/8) * x^( - 3/2).-If you know that √x = x^(1/2), and that 1/(√x) = x^(-1/2), then youll see that this is a very basic application of the power rule. Im not sure which it is, but this should be enough information to make the problem very simple.......
Hello! My question is Find the derivative of each function defined as follows y=6/4√x

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If the square root is in the denominator then the derivative of this problem is:
(negative) - [6/8] * x ^ (-3/2).

rewrite the expression as [6/4] * x^( - 1/2)
Then: (- 1/2) * (6/4) * x^( - 1/2 -- 2/2)
Which is: ( - 6/8) * x^( - 3/2).

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If you know that √x = x^(1/2), and that 1/(√x) = x^(-1/2), then you'll see that this is a very basic application of the power rule. I'm not sure which it is, but this should be enough information to make the problem very simple.
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