So here is a reaction: NaHSO4 + NaHCO3 ----> Na2SO4 + H2O + CO2. How much Sodium Bisulfate, Sodium Bicarbonate, and water do I need to react all of the chemicals?
-
It looks like the formula is balanced (two sodiums on the left, two on the right, etc.) and so now you just need to find their mass.
Get a periodic table. Each element has two numbers. For example, sodium is #11, and the two numbers associated are 11 and 22.99. Use the larger number; this is the mass. For NaHSO4 you need to add all of the masses. I will round each to two decimal points. Remember there are four oxygens.
Na 22.99
H 1.01
S 32.07
O 16.00 x 4 =64.00
Add them up and get
120.07
That's the mass in grams of one mole (unit) of NaHSO4
Follow that pattern and you should be able to solve the whole thing.
Get a periodic table. Each element has two numbers. For example, sodium is #11, and the two numbers associated are 11 and 22.99. Use the larger number; this is the mass. For NaHSO4 you need to add all of the masses. I will round each to two decimal points. Remember there are four oxygens.
Na 22.99
H 1.01
S 32.07
O 16.00 x 4 =64.00
Add them up and get
120.07
That's the mass in grams of one mole (unit) of NaHSO4
Follow that pattern and you should be able to solve the whole thing.
-
You need Sodium Bisulfate and Sodium Bicarbonate in a 1:1 molar ratio. You would figure the molecular weight of Sodium Bisulfate by adding up the atomic weight of all the atoms in it - sodium once, hydrogen once, sulfur once and oxygen 4 times. Do the same for Sodium Bicarbonate. I'm not going to do it for you, but let;s just say you get 50 and 45 respectively. Then if you have 50 grams of NaHSO4, you need 45 grams of NaHCO3 to completely react with it. If you have 10 grams of NaHSO4, you would need 10 x 45 / 50 = 9 grams of NaHCO3 to completely react with it. Bear in mind I made up those molecular weights. You need to calculate them for yourself using the real numbers.
-
I will give you a general example, so you can see how to solve all problems of similar type:
2A + 3B ----------> C + 4D
So you are given A and B, and by the compound and the MW, you can determine how many moles. In my example, you need 2 moles of A and 3 moles of B to react completely, and you will get 1 mole of C and 4 moles of D.
So if you have 2 moles of A and 4 moles of B, then B is in excess, since the number of moles of A determines how much product you can get.
In your question, water is a product, so it comes from the reactants, not added to them.
2A + 3B ----------> C + 4D
So you are given A and B, and by the compound and the MW, you can determine how many moles. In my example, you need 2 moles of A and 3 moles of B to react completely, and you will get 1 mole of C and 4 moles of D.
So if you have 2 moles of A and 4 moles of B, then B is in excess, since the number of moles of A determines how much product you can get.
In your question, water is a product, so it comes from the reactants, not added to them.