z = sqrt(x^2+y^2) and z = 6 - x^2-y^2
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Since z^2 = x^2 + y^2 (and z is non-negative), we have
z = 6 - z^2
==> z^2 + z - 6 = 0
==> z = 2. (we ignore z = -3, since z < 0)
I hope this helps!
z = 6 - z^2
==> z^2 + z - 6 = 0
==> z = 2. (we ignore z = -3, since z < 0)
I hope this helps!