If you have 75.0 mL of 3.0 M HCl, how do you calculate the number of mols? *The density of a dilute aqueous solution is 1.01 g/mL.
Can someone please help me calculate the correct number of mols? I have now done all the calculations on my lab report TWICE using the wrong number of mols. What am I doing wrong?
Can someone please help me calculate the correct number of mols? I have now done all the calculations on my lab report TWICE using the wrong number of mols. What am I doing wrong?
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For this calculation you do not require the density of the solution:
A 3.0M solution of HCl contains 3.0mol HCl in 1000 mL of solution
Mol HCl in 75mL of solution = 75/1000* 3.0 = 0.225 mol HCl
I came back to edit this:
Are you sure that the question is not based on a 3.0m solution of HCl?
Or was the word molality used - not molarity ?
Do you know the difference between these solutions?
A 3.0M solution of HCl contains 3.0mol HCl in 1000 mL of solution
Mol HCl in 75mL of solution = 75/1000* 3.0 = 0.225 mol HCl
I came back to edit this:
Are you sure that the question is not based on a 3.0m solution of HCl?
Or was the word molality used - not molarity ?
Do you know the difference between these solutions?