Calculus Question Below:

Let F(s) = 1.1s + 0.03x^2 represent the stopping distance (in feet) of a car traveling at s miles per hour. Calculate F(40) and estimate the increase in stopping distance if speed is increased from 40 to 41 . Compare your estimate with the actual increase. PS: I already found the estimated increase in stopping distance below, but don't know how to do the others. Thank you for your help:)

F (40) = ___________ feet
Estimated increase in stopping distance: 3.5 feet
Actual increase in stopping distance:_________ feet

First, I assume you meant to write F(s) = 1.1s + 0.03s^2
F(40) = 92 ft
Estimated increase = F'(40) = 1.1 + .06(40) = 3.5 ft
F(41) = 1.1*(41) + .03*(1681) = 95.53 ft
Actual increase = F(41) - F(40) = 95.53 - 92 = 3.53 ft