What is the rule that makes it wrong to say √ ̅(̅-̅1̅6̅)̅³̅ ̅ ̚ = √ ̅̅-̅1̅6̅̅ ̅ ̚ √ ̅̅-̅1̅6̅̅ ̅ ̚ √ ̅̅-̅1̅6̅̅
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HOME > > What is the rule that makes it wrong to say √ ̅(̅-̅1̅6̅)̅³̅ ̅ ̚ = √ ̅̅-̅1̅6̅̅ ̅ ̚ √ ̅̅-̅1̅6̅̅ ̅ ̚ √ ̅̅-̅1̅6̅̅

What is the rule that makes it wrong to say √ ̅(̅-̅1̅6̅)̅³̅ ̅ ̚ = √ ̅̅-̅1̅6̅̅ ̅ ̚ √ ̅̅-̅1̅6̅̅ ̅ ̚ √ ̅̅-̅1̅6̅̅

[From: ] [author: ] [Date: 12-06-25] [Hit: ]
i=sqr…-The formula √(ab)=√a x √b is valid only if at least one of a,b is +ve.1=√1 =√{(-1)x(-1)}=√-1 x √-1 = i x i = i^2 =-1. So 1=-1. Step 3 is invalid here. Your infringes the same rule.......
sqrt[(-16)³] ≠ sqrt((-16))*sqrt((-16))*sqrt((-16))
http://www.wolframalpha.com/input/?i=sqr…

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The formula √(ab)=√a x √b is valid only if at least one of a,b is +ve. Consider the following:
1=√1 =√{(-1)x(-1)}=√-1 x √-1 = i x i = i^2 =-1. So 1=-1. Step 3 is invalid here. Your infringes the same rule.
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