Okay so first off, i am not asking anyone to do my work for me. i have done the question, but i have done it in two different ways and cannot figure out which one is correct. This pertains to writing quadratic equations in standard form. The original equation that needed to be transferred is as follows: x=x(600-3x)-2(600-3x)-180
My first attempt at converting it to standard form is as follows:
x=(x)(600)+(x)(-3x)+(-2)(600)+(-2)(-3x…
=600x+(-3x exponent 2)+(-1200)+6x-180
=606x-3x exponent2-1380
the other equation i came up with for the same question is:
x=600x-3x-600+6x-180
=603x -780
if anyone can tell me which of the two i did properly (assuming one of the two is correct) it would be greatly appreciated.
My first attempt at converting it to standard form is as follows:
x=(x)(600)+(x)(-3x)+(-2)(600)+(-2)(-3x…
=600x+(-3x exponent 2)+(-1200)+6x-180
=606x-3x exponent2-1380
the other equation i came up with for the same question is:
x=600x-3x-600+6x-180
=603x -780
if anyone can tell me which of the two i did properly (assuming one of the two is correct) it would be greatly appreciated.
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the 2nd is not a quadratic , it's a linear equation
the 1st
x=606x-3x exponent2-1380 ---> 3x^2 - 605x + 1380 = 0
the 1st
x=606x-3x exponent2-1380 ---> 3x^2 - 605x + 1380 = 0