deviation is 20 points. Find the probability that the mean aptitude test score for a randomly selected group of 150 8th graders is between 101.5 and 98.5.
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P(x< 98.5) = P(z < (98.5-100)/20/sqrt(150)) = P(z < -0.9186) = 0.1792
P(x< 101.5) = P(z < (101.5-100)/20/sqrt(150)) =P(z < 0.91856) = 0.8208
difference = .6416
P(x< 101.5) = P(z < (101.5-100)/20/sqrt(150)) =P(z < 0.91856) = 0.8208
difference = .6416