How do i find the vertex of this parabola

I cannot find my notes and I am studying my finals. I cannot find this online either.
The equation
x=1/8(y-4)^2+6
I do not know the vertex
I know that if the equation was
y=1/8(x-4)^2+6
the vertex would be (4,6)
would the vertex of x=1/8(y-4)^2+6 be (6,4)?

Since for y=1/8(x-4)^2+6, you know the vertex is (4, 6).
Switch x and y, for x=1/8(y-4)^2+6, the vertex would be (6, 4).

The vertex would be (6,4)