f(x)= 14-5x-x^2. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relative maxima (minima).
1.
f is increasing on the intervals
2.
f is decreasing on the intervals
3.
The relative maxima of f occur at x =
4.
The relative minima of f occur at x =
1.
f is increasing on the intervals
2.
f is decreasing on the intervals
3.
The relative maxima of f occur at x =
4.
The relative minima of f occur at x =
-
f'(x)=-5-2x
x=-5/2
-infinity -7 -5/2 0 2 +infinity
--------------------------------------…
-------------0+++++81/4++14+0---------
-7 and 2 are the zero's of the f(X)
and for f'(x)=0 is a local min/max
1.
f is increasing on the intervals (-infinity;-5/2)
2.
f is decreasing on the intervals (-5/2, infinity)
3.
The relative maxima of f occur at x = -5/2
4.
The relative minima of f occur at x = does NOT have any as f'(x) has only one solution.
x=-5/2
-infinity -7 -5/2 0 2 +infinity
--------------------------------------…
-------------0+++++81/4++14+0---------
-7 and 2 are the zero's of the f(X)
and for f'(x)=0 is a local min/max
1.
f is increasing on the intervals (-infinity;-5/2)
2.
f is decreasing on the intervals (-5/2, infinity)
3.
The relative maxima of f occur at x = -5/2
4.
The relative minima of f occur at x = does NOT have any as f'(x) has only one solution.