Let f(x) = g(h(x)), where h(2) = 3, h'(2) = 4, g(3) = 2, and g'(3) = 5. Find f'(2). (I'm not sure how to solve this. Maybe more information is needed?)
-
Chain rule: f '(x) = h'(x) * g'(h(x))
f '(2) = h'(2) * g'(h(2)) = 4*g'(3) = 4*5 = 20
f '(2) = h'(2) * g'(h(2)) = 4*g'(3) = 4*5 = 20