3+or- squareroot -57/4
-
Its not a quadratic but this is how you would solve it !
original problem : 3±√-57/4
1st. √-57/4 can be separated into two square roots √-57 and √4
2nd. there no square root of -57 but the square root of 4 is 2 the problem now becomes 3±√-57/2
3rd. there cant be a negative under the square root, bring it out the negative it become and "i" for imaginary.
ANSWER = 3±√57/2 i
original problem : 3±√-57/4
1st. √-57/4 can be separated into two square roots √-57 and √4
2nd. there no square root of -57 but the square root of 4 is 2 the problem now becomes 3±√-57/2
3rd. there cant be a negative under the square root, bring it out the negative it become and "i" for imaginary.
ANSWER = 3±√57/2 i
-
[3 ± √(- 57)]/4
is a complex number, not a quadratic (anything) ! Re-read your problem and repost !
@Σ
is a complex number, not a quadratic (anything) ! Re-read your problem and repost !
@Σ