What is the equation in point-slope form of the line passing through (–2, 0) and (2, 8)?
please help me out with this question, I have 4 choices narrowed down, thanks in advanced to anyone who answers, I really appreciate it.
y = 2(x + 2)
y = 2(x – 2)
y = –2(x – 2)
y = –2(x + 2)
please help me out with this question, I have 4 choices narrowed down, thanks in advanced to anyone who answers, I really appreciate it.
y = 2(x + 2)
y = 2(x – 2)
y = –2(x – 2)
y = –2(x + 2)
-
First, find the slope:
(y1 - y2) / (x1 - x2)
(0 - 8) / (-2 - 2)
-8 / -4
2
Point-slope:
y - y1 = m(x - x1)
y - 0 = 2(x - -2)
y = 2(x + 2)
(y1 - y2) / (x1 - x2)
(0 - 8) / (-2 - 2)
-8 / -4
2
Point-slope:
y - y1 = m(x - x1)
y - 0 = 2(x - -2)
y = 2(x + 2)
-
slope is (8 - 0)/( 2 - -2) = 2
so y = 2x + c
substituting for (-2, 0)
0 = -4 + c
so c = +4
y = 2(x + 2)
so y = 2x + c
substituting for (-2, 0)
0 = -4 + c
so c = +4
y = 2(x + 2)