What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-in

What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?

y = 3x + 4

y = x + 3

y = –3x – 6

y = x – 5

I am getting 1/3x+3, but i dont see it as an answer choice.

None of your answer choices can possibly be correct !

perpendicular lines have slopes that are negative reciprocals of each other...

(m1) * (m2) = - 1

if the given line has a slope of: m = - 3

then the perpendicular line must have a slope of: m = 1/3

none of the given equations has a slope of 1/3...

Go back to your problem, re-read it, and repost with correct information !

qed

[the correct equation is: y = (x/3) + 3]

y - 1 = 1/3 (x - (-6))
y - 1 = 1/3 x +2
y = 1/3x + 3
Thats what I got but i could be wrong if those are multiple choices i would go with y = x + 3