I have what is known as dyscalculia, and I have been doing this exercises since Friday and I can't seem to find the correct answer. Please help me. I will be really thankful.
Draw Graphic and find the intercepts for "y and x"
y=3/5x-2
y=-5x+2
II. Find the lineal equation that goes thru (3,-2) (-3,2) find intercepts
please don't write silly comments. I need this to pass the class, otherwise I would have to take it in summer.
Draw Graphic and find the intercepts for "y and x"
y=3/5x-2
y=-5x+2
II. Find the lineal equation that goes thru (3,-2) (-3,2) find intercepts
please don't write silly comments. I need this to pass the class, otherwise I would have to take it in summer.
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Draw Graphic and find the intercepts for "y and x"
y = (3/5)x - 2
I'm assuming that's the equation and not 3/(5x).
The line has a slope of 3/5. It rises by 3 units of y for each 5-unit increase in x. It crosses the y-axis (x = 0) at point (0, -2).
Plot a point at (0, -2).
Plot a second point 5 units to the right (x = 0 + 5 = 5) and 3 units up (y = -2 + 3 = 1). Plot the point at (5, 1).
Draw the first line through those two points.
y = -5x + 2
This line has a slope of -5. It falls 5 unis of y for each 1-unit increase ix x. It crosses the y-axis (x = 0) at point (0, 2).
Plot a point at (0, 2).
Plot a second point 1 unit to the right (x = 0 + 1 = 1) and 5 units down (y = 2 - 5 = -3). Plot the point at (1, -3).
Draw the second line through those two points.
The solution is the point where the two lines intersect. Read them from the graph.
II. Find the lineal equation that goes thru (3,-2) (-3,2) find intercepts
Fisrt find the slope, the change in y divided by the change in x. The y value changes by 4 (from -2 to 2) while the x value changes by -6 (from 3 to -3). That makes the slope 4/-6 which reduces to -2/3.
The partial equation is y = (-2/3)x + b where b is the y-intercept. To solve for b, insert the x and y coordinates for either of the known points and solve for it.
Using equation 1:
y = (-2/3)x + b
-2 = (-2/3)(3) + b
Multiply:
-2 = -2 + b
Add 2 to both sides:
0 = b
The full equation is:
y = (-2/3)x + 0 or y = (-2/3)x
The line slopes down by 2 units of y for each 3-unit increase in x. It passes through the origin at point (0, 0) since when x equals zero, so does y.
y = (3/5)x - 2
I'm assuming that's the equation and not 3/(5x).
The line has a slope of 3/5. It rises by 3 units of y for each 5-unit increase in x. It crosses the y-axis (x = 0) at point (0, -2).
Plot a point at (0, -2).
Plot a second point 5 units to the right (x = 0 + 5 = 5) and 3 units up (y = -2 + 3 = 1). Plot the point at (5, 1).
Draw the first line through those two points.
y = -5x + 2
This line has a slope of -5. It falls 5 unis of y for each 1-unit increase ix x. It crosses the y-axis (x = 0) at point (0, 2).
Plot a point at (0, 2).
Plot a second point 1 unit to the right (x = 0 + 1 = 1) and 5 units down (y = 2 - 5 = -3). Plot the point at (1, -3).
Draw the second line through those two points.
The solution is the point where the two lines intersect. Read them from the graph.
II. Find the lineal equation that goes thru (3,-2) (-3,2) find intercepts
Fisrt find the slope, the change in y divided by the change in x. The y value changes by 4 (from -2 to 2) while the x value changes by -6 (from 3 to -3). That makes the slope 4/-6 which reduces to -2/3.
The partial equation is y = (-2/3)x + b where b is the y-intercept. To solve for b, insert the x and y coordinates for either of the known points and solve for it.
Using equation 1:
y = (-2/3)x + b
-2 = (-2/3)(3) + b
Multiply:
-2 = -2 + b
Add 2 to both sides:
0 = b
The full equation is:
y = (-2/3)x + 0 or y = (-2/3)x
The line slopes down by 2 units of y for each 3-unit increase in x. It passes through the origin at point (0, 0) since when x equals zero, so does y.