the second side of a triangle is 4 inches longer than the first side. the third side of the triangle is 3 inches longer than the second side. if the perimeter of the triangle is 101 inches, find the length of the third side of the triangle.
-
Let the length of the first side be x
the length of the second side will be x + 4
the length of the third side will be x + 4 + 3 = x + 7, so:
x + x + 4 + x + 7 = 101, so
3x + 11 = 101, so:
3x = 90, so
x = 30.
The length of the third side = 37
the length of the second side will be x + 4
the length of the third side will be x + 4 + 3 = x + 7, so:
x + x + 4 + x + 7 = 101, so
3x + 11 = 101, so:
3x = 90, so
x = 30.
The length of the third side = 37
-
1st Side - x
2nd side - x+4
3rd Side - x+7
3x + 11 = 101 (-11)
3x = 90 (/3)
x=30
first side = 30 inches
second side = 34 inches
third side = 37 inches
2nd side - x+4
3rd Side - x+7
3x + 11 = 101 (-11)
3x = 90 (/3)
x=30
first side = 30 inches
second side = 34 inches
third side = 37 inches
-
the third side =x
===>
2nd side = x-3
1st side = x-7
perimeter = x + (x-3)+(x-7)=101 , now solve for x
===>
2nd side = x-3
1st side = x-7
perimeter = x + (x-3)+(x-7)=101 , now solve for x