heres a question I'm not sure how to do.
Find the the limit.
Lim x--> infinity
(5x^4 + 7x^3 + 6) / (2x^4 + 3x^2 +7)
I'm aware that i can multiply through by the highest power....i think, but I'm not exactly sure how it works.
Working would be awesome, thanks!
Find the the limit.
Lim x--> infinity
(5x^4 + 7x^3 + 6) / (2x^4 + 3x^2 +7)
I'm aware that i can multiply through by the highest power....i think, but I'm not exactly sure how it works.
Working would be awesome, thanks!
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Actually, you divide through by the highest power.
(5 + (7/x) + (6/x^4)) / (2 + (3/x^2) + (7/x^4))
As x goes to infinity, all the terms with an x in the numerator become zero, so we simply get
5/2
Note, this is always a great way to check these limits.
If the highest power in the numerator is equal to the highest power in the denominator, the limit at infinity will always be the ratio of their coefficients, which this shows, as 5 and 2 were the coefficients with the highest powers. Cheers!
(5 + (7/x) + (6/x^4)) / (2 + (3/x^2) + (7/x^4))
As x goes to infinity, all the terms with an x in the numerator become zero, so we simply get
5/2
Note, this is always a great way to check these limits.
If the highest power in the numerator is equal to the highest power in the denominator, the limit at infinity will always be the ratio of their coefficients, which this shows, as 5 and 2 were the coefficients with the highest powers. Cheers!