2x^2+6y^2+32x-48y+212=0
I dont get this cause the center is (-8,4) and the major is sqrt(6) and the minor is sqrt(2) but it wont let me put the answers in like that. Sooo Please help find major minor and distance from C to foci
I dont get this cause the center is (-8,4) and the major is sqrt(6) and the minor is sqrt(2) but it wont let me put the answers in like that. Sooo Please help find major minor and distance from C to foci
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2x^2 + 6y^2 + 32x - 48y + 212 = 0
2(x^2 + 16x) + 6(y^2 - 8y) = - 212
2(x^2 + 16x + 64) + 6(y^2 - 8y + 16) = - 212 + 2*64 + 6*16
2(x + 8)^2 + 6(y - 4)^2 = 12
(x + 8)^2 /(6) + (y - 4)^2 / (2)= 1
---------
center = (-8, 4)
a = √6
b = √2
focal length = √(6 - 2) = √4 = 2
as far as I can see, this is correct
see also
http://www.wolframalpha.com/input/?i=+2x…
OG
2(x^2 + 16x) + 6(y^2 - 8y) = - 212
2(x^2 + 16x + 64) + 6(y^2 - 8y + 16) = - 212 + 2*64 + 6*16
2(x + 8)^2 + 6(y - 4)^2 = 12
(x + 8)^2 /(6) + (y - 4)^2 / (2)= 1
---------
center = (-8, 4)
a = √6
b = √2
focal length = √(6 - 2) = √4 = 2
as far as I can see, this is correct
see also
http://www.wolframalpha.com/input/?i=+2x…
OG