Solve for b, please help
Favorites|Homepage
Subscriptions | sitemap
HOME > > Solve for b, please help

Solve for b, please help

[From: ] [author: ] [Date: 12-04-29] [Hit: ]
Cancel the common factor of b in 2b/ab.Find the LCD (least common denominator) of a+2/a-1=c.Multiply each term in the equation by a in order to remove all the denominators from the equation.Simplify the left-hand side of the equation by canceling the common factors.Since ac contains the variable to solve for, move it to the left-hand side of the equation by subtracting ac from both sides.......
solve for b

c=a+2b/ab-1

I know this is easy but I'm having a mind block right now studying for the final. I know the answer is
b=a+c/ac-2 but how?

-
http://www.flickr.com/photos/dwread/6976…

-
Since b is on the right-hand side of the equation switch the sides so it is on the left-hand side of the equation.

a+2b/ab-1=c

Cancel the common factor of b in 2b/ab.

a+2/a-1=c

Find the LCD (least common denominator) of a+2/a-1=c.
LCD:a
Multiply each term in the equation by a in order to remove all the denominators from the equation.

a*a+2*a-1=c*a

Simplify the left-hand side of the equation by canceling the common factors.

a^20a+2=ac

Since ac contains the variable to solve for, move it to the left-hand side of the equation by subtracting ac from both sides.

a^2-a+2-ac=0

Move all terms not containing a to the right-hand side of the equation.

a^2-a-ac+2=0

Use the quadratic formula to find the solutions. In this case, the values are a=1,b=-1, and c=-1c+2.

Substitute in the values of a=1, b=-1, and c=-1c+2.

a=(-(-1)[plus or minus sign]√(-1)^2-4(1)(-1c+2) )/(2(1))

Notice: The first and last parentheses before the "/" and after, are used to show that they are on top and bottom of a fraction. You do not have to worry about the parentheses before the "-(-1)", after the "2)", and before and after the "2(1)".

Simplify the section inside the radical.
a=( 1[plus or minus sign]√(4c-7) )/( 2 )

The final answer is the combination of both solutions.
a=( 1+√( 4c-7 )/( 2 ), ( 1-√( 4c-7 )/( 2 )

Check that all solutions found are valid and are part of the domain by substituting them into the original equation.

b=( 1+√( 4c-7 )/( 2 ), ( 1-√( 4c-7 )/( 2 )

Sorry. Not quite sure how you got b=a+c/ac-2, and I am sure that I did it correctly. I am very good at math :D.

Oh and in addition before I submit... I love how you play WoW. I play as well!:P Just saying.

-
2b/ab = 2/a, leaving no b

Did you mean (a+2b) / (ab-1) or ( (a+2b) / (ab) ) - 1 or maybe a + (2b / (ab - 1)), or something else?

-
cab-c = a+2b
b(ac-2)=a+c
b = (a+c)/(ac-2)
1
keywords: please,for,help,Solve,Solve for b, please help
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .