Suppose ages of cars driven by company employees are normally distributed with a mean of 8 years and a standard deviation of 3.2 years. Approximately 75% of cars driven by company employees are older than what age?
about 10.2 years
about 5.9 years
about 4.8 years
about 2.1 years
about 10.2 years
about 5.9 years
about 4.8 years
about 2.1 years
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Let X be the ages of cars driven by company employees.
X ∼ n(8; 3.2)
P(X ≥ x) = 0.75
P((X - 8)/3.2 ≥ (x - 8)/3.2) = 0.75
P(Z ≥ - z) = 0.75
z = - 0.675
- 0.675 = (x - 8)/3.2
x = 5.84years!
X ∼ n(8; 3.2)
P(X ≥ x) = 0.75
P((X - 8)/3.2 ≥ (x - 8)/3.2) = 0.75
P(Z ≥ - z) = 0.75
z = - 0.675
- 0.675 = (x - 8)/3.2
x = 5.84years!