determine algebraically whether the given function is even, odd or neither
f(x)=-2x^4+3x^2
please step by step so i can understand it. thank you
f(x)=-2x^4+3x^2
please step by step so i can understand it. thank you
-
if
f(-x) = f(x), then it is even
if
f(-x) = -f(x), then it is odd
otherwise, it is neither
so
f(-x) = -2(-x)^4 + 3(-x)^2
= -2x^4 + 3x^2
thus
it is even
♣♦
f(-x) = f(x), then it is even
if
f(-x) = -f(x), then it is odd
otherwise, it is neither
so
f(-x) = -2(-x)^4 + 3(-x)^2
= -2x^4 + 3x^2
thus
it is even
♣♦