Hello so I am a bit confused with this question. How exactly do I find angle A?
This is what I did.
tanA=-2/6 becomes tanA=-0.3
A=tan^-1(0.3)
-16.7+180degrees=163.3degrees
Not sure if that is correct but if it is correct I don't know where to go from here in order to find the second possible value for angle A.
Also I've determined that the two values are located in the 2nd and 4th quadrants.
This is what I did.
tanA=-2/6 becomes tanA=-0.3
A=tan^-1(0.3)
-16.7+180degrees=163.3degrees
Not sure if that is correct but if it is correct I don't know where to go from here in order to find the second possible value for angle A.
Also I've determined that the two values are located in the 2nd and 4th quadrants.
-
-2/6 does not equal -0.3
tan^-1(-2/6) = -18.4
-18.4 + 180 = 161.6
161.6 + 180 = 341.6
Angle A could therefore be 161.6 or 341.6
tan^-1(-2/6) = -18.4
-18.4 + 180 = 161.6
161.6 + 180 = 341.6
Angle A could therefore be 161.6 or 341.6