If an investment of $1500 grows to $1953.39 in

If an investment of $1500 grows to $1953.39 in six years with interest compounded annually, what is the interest rate? (Round your answer to one decimal place.)

A = P[1 + r]^t

1953.39 = 1500[1 + r]^6

1953.39 / 1500 = [1 + r]^6

(1953.39 / 1500)^(1/6) = 1 + r

(1953.39 / 1500)^(1/6) - 1 = r

0.04499998330266273862985170285459 = r

.045
4.5%