I need some help with steps, there's a table but I can't copy and paste so I will list values, I apologize for this.
x = 5, f(x) = a
x = 10, f(x) = 32
x = 15 , f(x) = b
If f is a linear function, what is value of a + b?
x = 5, f(x) = a
x = 10, f(x) = 32
x = 15 , f(x) = b
If f is a linear function, what is value of a + b?
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64.
Since f(x) is a linear function, it has the form f(x) = mx + c.
f(5) = 5m + c = a
f(10) = 10m + c = 32
f(15) = 15m + c = b
a + b =
(5m + c) + (15m + c) =
20m + 2c =
2(10m + c) =
2(32) =
64.
Since f(x) is a linear function, it has the form f(x) = mx + c.
f(5) = 5m + c = a
f(10) = 10m + c = 32
f(15) = 15m + c = b
a + b =
(5m + c) + (15m + c) =
20m + 2c =
2(10m + c) =
2(32) =
64.
-
If it is a linear function, then the slope or rate of change has to be identical.
You are given a point (10, 32) and two others with variables (5, a) and (15, b)
Use your formula for slope (y1 - y2)/(x1 - x2) where (x1, y1) and (x2, y2) are given points on the line
(32 - a) / (10 - 5) = (32 - a) / 5
(b - 32) / (15 - 10) = (b - 32) / 5
(b - a) / (15 - 5) = (b - a) / 10
All these values are equal
(32 - a)/ 5 = (b - a) / 10 Multiply both side by 10
2(32 - a) = b - a
64 - 2a = b - a
64 = b + a
You are given a point (10, 32) and two others with variables (5, a) and (15, b)
Use your formula for slope (y1 - y2)/(x1 - x2) where (x1, y1) and (x2, y2) are given points on the line
(32 - a) / (10 - 5) = (32 - a) / 5
(b - 32) / (15 - 10) = (b - 32) / 5
(b - a) / (15 - 5) = (b - a) / 10
All these values are equal
(32 - a)/ 5 = (b - a) / 10 Multiply both side by 10
2(32 - a) = b - a
64 - 2a = b - a
64 = b + a