Can you think of an integer x and y so that x^2=y^3

Can you think of an integer x and y that are greater than 1. so that x^2=y^3 Any help is appreciated. Thank you

x=8
y=4

Also, I understood the question and gave that exact answer, as well as a solution to every correct answer. And my buddy Jamilur also gave the correct answer by copying and pasting my solution.

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Solve: For all positive integers i, x = i^3 and y = i^2.

That means…
x = 8, y = 4
x = 27, y = 9
x = 64, y = 16

For all positive integers i, x = i^3 and y = i^2.

That means…
x = 8, y = 4
x = 27, y = 9
x = 64, y = 16
and so on