Maths - determining the avg value of a polynomial function on the interval

On the domain 0 < x < 2pi/3 the polynomial p(x) = x-x^2+ 1/3x^3 - 1/30x^5+ 190x^6 - 1/630 x^ 7 is a good approximation
to the function f(x) = e^-x sin(x).
Find the average value of the function f(x) by;
(a) Determining the average value of the function p(x) on the interval

I am just really confuesd on how to start this

Any help would be greatly appriciated :)

The average value of a function f(x) on the interval a < x < b is given by:
1/(b-a) * ∫f(x)dx (from a to b)

In this case, we want to find the average value of p(x) on the interval 0
Hope that helps :)