I have no idea how to calculate APR or monthly payments :)
Also what would the total interest that's paid on the loan?
Does anybody know of a website that has a calculator for this kind of thing?
Also what would the total interest that's paid on the loan?
Does anybody know of a website that has a calculator for this kind of thing?
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I'll show you how to calculate monthly payments.
Let's suppose you had a loan that you needed to repay in 3 payments, and you were charged "i" annual interest
L = loan amount
i = interest rate
P = monthly payment
(((L * (1 + i/12) - P) * (1 + i/12) - P) * (1 + i/12) - P = 0
Let 1 + i/12 = r
(((L * r - P) * r - P) * r - P = 0
Solve for L
((Lr - P) * r - P = P/r
Lr - P = P/r + P/r^2
L = P/r + P/r^2 + P/r^3
L = P * ((1/r) + (1/r)^2 + (1/r)^3)
Now, if you've ever learned about geometric sums, you'd recognize (1/r) + (1/r)^2 + (1/r)^3 as a sum. Now, before I solve that sum (make it easier to manage), let's suppose that we had a different number of payments. We'll call that number "n"
L = P * ((1/r) + (1/r)^2 + (1/r)^3 + ... + (1/r)^n)
Can we make it easier to manage? Absolutely!
Let (1/r) = t, and let (1/r) + (1/r)^2 + ... + (1/r)^n sum to S
S = (1/r) + (1/r)^2 + ... + (1/r)^n
S = t + t^2 + t^3 + ... + t^n
Multiply both sides by t and solve for S
S * t = t * (t + t^2 + t^3 + ... + t^n)
S * t = t^2 + t^3 + t^4 + ... + t^(n + 1)
S - St = t + t^2 - t^2 + t^3 - t^3 + .... + t^n - t^n - t^(n + 1)
Notice most terms cancel out on the right hand side
S - St = t - t^(n + 1)
S - St = t * (1 - t^n)
S * (1 - t) = t * (1 - t^n)
S = t * (1 - t^n) / (1 - t)
So:
t + t^2 + t^3 + .... + t^n = t * (1 - t^n) / (1 - t)
L = P * S
L = P * t * (1 - t^n) / (1 - t)
P = L * (1 - t) / (t * (1 - t^n))
t = 1/r
r = 1 + i/12
First, let's calculate monthly payments
L = 24000
n = 10 * 12 = 120 payments
Let's suppose you had a loan that you needed to repay in 3 payments, and you were charged "i" annual interest
L = loan amount
i = interest rate
P = monthly payment
(((L * (1 + i/12) - P) * (1 + i/12) - P) * (1 + i/12) - P = 0
Let 1 + i/12 = r
(((L * r - P) * r - P) * r - P = 0
Solve for L
((Lr - P) * r - P = P/r
Lr - P = P/r + P/r^2
L = P/r + P/r^2 + P/r^3
L = P * ((1/r) + (1/r)^2 + (1/r)^3)
Now, if you've ever learned about geometric sums, you'd recognize (1/r) + (1/r)^2 + (1/r)^3 as a sum. Now, before I solve that sum (make it easier to manage), let's suppose that we had a different number of payments. We'll call that number "n"
L = P * ((1/r) + (1/r)^2 + (1/r)^3 + ... + (1/r)^n)
Can we make it easier to manage? Absolutely!
Let (1/r) = t, and let (1/r) + (1/r)^2 + ... + (1/r)^n sum to S
S = (1/r) + (1/r)^2 + ... + (1/r)^n
S = t + t^2 + t^3 + ... + t^n
Multiply both sides by t and solve for S
S * t = t * (t + t^2 + t^3 + ... + t^n)
S * t = t^2 + t^3 + t^4 + ... + t^(n + 1)
S - St = t + t^2 - t^2 + t^3 - t^3 + .... + t^n - t^n - t^(n + 1)
Notice most terms cancel out on the right hand side
S - St = t - t^(n + 1)
S - St = t * (1 - t^n)
S * (1 - t) = t * (1 - t^n)
S = t * (1 - t^n) / (1 - t)
So:
t + t^2 + t^3 + .... + t^n = t * (1 - t^n) / (1 - t)
L = P * S
L = P * t * (1 - t^n) / (1 - t)
P = L * (1 - t) / (t * (1 - t^n))
t = 1/r
r = 1 + i/12
First, let's calculate monthly payments
L = 24000
n = 10 * 12 = 120 payments
12
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