What is the formula for 3c^2 - 2c -2 = 0

What is the formula that would get me from 3c^2 - 2c -2 = 0 to c = (2+/- (4+24)^1/2) / 6

Use the quadratic formula.

x = (-b +/- sart(b^2-4ac))/2a

I hope this information was very helpful.

that is called the quadratic equation:

C = (- b ± √b² - 4ac)/ 2a

you just plug in the coefficients of the terms in the quadratic

a corresponds to the number on the c squared, b is on the middle term, and c is the constant:

in this case, a = 3 b = -2 and c = -2

plug these into the above equation and you will get that mess you have there.

this gives you the zeros of the quadratic

just a little note, the 1/2 exponent is the same as taking the square root, so hopefully that doesn't throw you off.

i also used a capital C just to show the difference between the unknown variable being solved for, and the known constant, c.

For a quardatic eqution
ax 2 bx c = 0 , the value of x is given by:

x={-b -(b^2-4ac)^(1/2)}/2a

4 mor details go to

Quadratic equation.

for ax^2+bx+c=0

x = (-b +/- Sqrt[b^2-4ac])/2a