Explain y in terms of x,it is given that 3x+y-12=0.check whether point(3,3),(4,0),and(2,12) satisfy the

Equation 3x+y-12=0(without using graph)

3x+y-12=0
y=12-3x
point(3,3)
When x=3
12-3x= 12-9=3
point(3,3) satisfy
****
(4,0)
When x=4
12-3x= 12-12=0
point(4,0) satisfy
*******
(2,12)
When x=2
12-3x= 12-6=6
point (2,12) does NOT satisfy

3x+y-12=0
3x=12-y
x=(12-y)/3

now take first point(3,3)
put x=3 and y=3
3=(12-3)/3
3=9/3
3=3
LHS=RHS
point one satisfies

similarly for 2nd point x=4 and y=0
4=(12-0)/3
4=12/3
4=4
point 2 satisfies

point 3
x=2, y=12
2=(12-12)/0
2=0/0
here lhs is not equal to rhs.
therefore this point does not satisfy above equation.

for (3,3) plug in the first 3 = x and the 2nd 3 = y

3 x + y - 12 = 0
so 3(3) + (3) - 12 = 0
9 + 3 - 12 = 0
12 - 12 = 0

so yes that does satisfy.. do the same for the other 2...

(3,3) satisfies
(4,0) satisfies
(2,12) does not satisfy