let A be [[1 2] and B be [[-3 2]
............[2 4]]................[-1 -1]]
Find a matrix C for which the (2,2) entry is 0 and such that AB=AC and BA=CA
............[2 4]]................[-1 -1]]
Find a matrix C for which the (2,2) entry is 0 and such that AB=AC and BA=CA
-
Let C=[a b]
..........[c 0]
AB=[-5 0]
.......[-10 0]
AC=[a+2c b]
......[2a+4c 2b]
Since AB=AC then
Then a+2c=-5 and 2a+4c=-10 which is the same equation.b=0
BA=[1 2]
.......[-3 -6]
CA=[a+2b 2a+4b]
.......[c 2c]
You know that b=0 and since BA=CA then
a+2b=1 and 2a+4b=2 which are the same equation, then a=1
c=-3
Then C=[1 0]
..............[-3 0]
..........[c 0]
AB=[-5 0]
.......[-10 0]
AC=[a+2c b]
......[2a+4c 2b]
Since AB=AC then
Then a+2c=-5 and 2a+4c=-10 which is the same equation.b=0
BA=[1 2]
.......[-3 -6]
CA=[a+2b 2a+4b]
.......[c 2c]
You know that b=0 and since BA=CA then
a+2b=1 and 2a+4b=2 which are the same equation, then a=1
c=-3
Then C=[1 0]
..............[-3 0]
-
C matrix will look somewhat like this:
[X Y]
[Z 0]
You must find X,Y,Z and the conditions are specified.
AB=[-5 0]
[-10 0]
AC= [X+2Y Y ]
[2X+4Z 2Y]
Since AB=AC,
Y=0
X=-5
Z=0.
Substitute the values in matrix C=[X Y]
[Z 0]
[X Y]
[Z 0]
You must find X,Y,Z and the conditions are specified.
AB=[-5 0]
[-10 0]
AC= [X+2Y Y ]
[2X+4Z 2Y]
Since AB=AC,
Y=0
X=-5
Z=0.
Substitute the values in matrix C=[X Y]
[Z 0]