How do you solve this 8th grade Algebra Regents problem? x²+19x=-88

How do you solve this?

x²+19x= -88

Show step by step please :)

x^2 + 19x = -88
x^2 + 19x + 88 = 0
find factors of 88 that will add up to 19.
in this case, 11 & 8
(x + 11)(x + 8) = 0
equate each to 0 and solve for x

x + 11 = 0
x = -11

x + 8 = 0
x = -8

x = -11 and -8

How do you solve this 8th grade Algebra Regents problem? x²+19x=-88?
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rearrange the eq to x^2 + 19x + 88 = 0

notice that the factors of 88 are 11 and 8.

notice that if you add these factors, you get + 19,

which is the coefficient of the x-term.

The factors are: (x+11)(x+8) = 0, which means

the roots are -8 and -11.

x^2 + 19x = -88
x^2 + 19x + 88 =0
(x+8)(x+11)
As 11+8=11 and 11*8=88