how do you solve 3 over y = 9 over y minus 1 over 2?
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3/y=9/y-1/2
3/y - 9/y = -1/2
-6/y = -1/2
(y)(-6/y) = (-1/2)y
-6 = -1y/2
(-2)(-6) = (-2)(-1y/2)
12 = y
3/y - 9/y = -1/2
-6/y = -1/2
(y)(-6/y) = (-1/2)y
-6 = -1y/2
(-2)(-6) = (-2)(-1y/2)
12 = y