The sym of twice one number plus twice a second num is 14. the diff of the first # minus the 2nd # is 4. fnd #

Let x be the first number and y be the second number.

x: 1st number

y: 2nd number


2x + 2y = 14

x - y = 4

Now solve the system to get

x = 4 + y

Put this into the top equation to get

2(4 + y) + 2y = 14

8 + 2y + 2y = 14

8 + 4y = 14

y = 6/4 [which is the same as y = 1.5]

Now plug this into the bottom equation

x - 1.5 = 4

x = 5.5

Answer: x = 5.5 and y = 1.5


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Check:

2x + 2y = 14

2(5.5) + 2(1.5) = 14

11 + 3 = 14

14 = 14

(so the top equation holds)

Check the second (bottom equation)

x - y = 4

(5.5) - (1.5) = 4

4 = 4

(second equation holds)