Hi everyone can you please try helping me because I am stuck. Can you please explain how you did it as well. Thanks guys :)
1. Insert group symbols and operating signs (),+,-,x or divide (I can't see any division sign) to make the following number sequence true. 24 1 5 2 7 15=4
2. John runs around a circular track which is 3km long at the speed of 6km/h. At the same starting point Jack cycles round the circular track at the speed of 15km/h. If they start together at 9:00am, when will they meet again at the starting point?
Thanks everyone:)
1. Insert group symbols and operating signs (),+,-,x or divide (I can't see any division sign) to make the following number sequence true. 24 1 5 2 7 15=4
2. John runs around a circular track which is 3km long at the speed of 6km/h. At the same starting point Jack cycles round the circular track at the speed of 15km/h. If they start together at 9:00am, when will they meet again at the starting point?
Thanks everyone:)
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1).
((24 + 1) ÷ 5) + (2 x 7) - 15 = 4
2).
John runs around a circular track which is 3 km long at the speed of 6 km/h.
At the same starting point Jack cycles round the circular track at the speed of 15 km/h.
If they start together at 9:00 a.m., when will they meet again at the starting point?
The circular track is 3 km long.
John and Jack start together at 9 a.m.
John circles the track every 1/2 an hour.
Jack does it every 1/5th of an hour.
John : 1/2, 1, 1 1/2, 2, 2 1/2, 3, 3 1/2, .....
Jack : 1/5, 2/5, 3/5, 4/5, 1, .....
They meet again at the starting point at 10 a.m.
((24 + 1) ÷ 5) + (2 x 7) - 15 = 4
2).
John runs around a circular track which is 3 km long at the speed of 6 km/h.
At the same starting point Jack cycles round the circular track at the speed of 15 km/h.
If they start together at 9:00 a.m., when will they meet again at the starting point?
The circular track is 3 km long.
John and Jack start together at 9 a.m.
John circles the track every 1/2 an hour.
Jack does it every 1/5th of an hour.
John : 1/2, 1, 1 1/2, 2, 2 1/2, 3, 3 1/2, .....
Jack : 1/5, 2/5, 3/5, 4/5, 1, .....
They meet again at the starting point at 10 a.m.
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1. Insert group symbols and operating signs (),+,-,x or divide (I can't see any division sign) to make the following number sequence true. 24 1 5 2 7 15 = 4
24 -1 +5 -2 -7 -15 = 4
2. John runs around a circular track which is 3km long at the speed of 6km/h. At the same starting point Jack cycles round the circular track at the speed of 15km/h. If they start together at 9:00am, when will they meet again at the starting point?
Thanks everyone:)
John runs around the track in 3/6 = 1/2 hr
Jack runs around the track in 3/15 = 1/5 hr
when John runs 2 laps and Jack runs 5, they'll be at the same place
10:00 am
24 -1 +5 -2 -7 -15 = 4
2. John runs around a circular track which is 3km long at the speed of 6km/h. At the same starting point Jack cycles round the circular track at the speed of 15km/h. If they start together at 9:00am, when will they meet again at the starting point?
Thanks everyone:)
John runs around the track in 3/6 = 1/2 hr
Jack runs around the track in 3/15 = 1/5 hr
when John runs 2 laps and Jack runs 5, they'll be at the same place
10:00 am
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(24 + 1) / 5 + (2 * 7) - 15 = 4
25 / 5 + 14 - 15 = 4
5 + 14 - 15 = 4
19 - 15 = 4
4 = 4
x = *
Divide = /
2) When Jack's and John's distance travelled are divisible by 3 is when they will meet. Every 30min John crosses the line. Every 12 minutes Jack crosses the line.
9am 9:30am 10am
John 0 3km 6km
Jack 0 7.5km 15km
They will meet at the starting point at 10am.
25 / 5 + 14 - 15 = 4
5 + 14 - 15 = 4
19 - 15 = 4
4 = 4
x = *
Divide = /
2) When Jack's and John's distance travelled are divisible by 3 is when they will meet. Every 30min John crosses the line. Every 12 minutes Jack crosses the line.
9am 9:30am 10am
John 0 3km 6km
Jack 0 7.5km 15km
They will meet at the starting point at 10am.
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1. 24 - ((1+5)*2) + 7 - 15 = 4
2. 10:00 am, 10 points plz. :D
2. 10:00 am, 10 points plz. :D