Please help me get the answer to these math problems!
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Please help me get the answer to these math problems!

[From: ] [author: ] [Date: 12-02-11] [Hit: ]
E=18*1/3So you were right. 18 for the twins and 6 for Emily.Problem two: there isnt enough info to tell how many Katy got right, but I can te u how many were on the teast.X=number of 2 point problemsY=number of three point problemEquation 1:2x+3y=100Equation 2:X+y=42If you substitute just like last time:X+y=42 so y=42-xThe variable cross each other out and:42=42The answer Js I.finite number of solutions.......
Equation 2: (Since J=L, you can use J+J instead of J+L)
J+J+E=42

In this case, the substitution method would be a lot easier than elimination.

Substitution (J*1/3) in for E into the second equation and solve for J.

J+j+j*1/3=42

Multiply by 3 to get rid of the fraction

3J+3j+j=126
7j=126
J=18

Now that you know j, u can plug that back into the first equation.

E=18*1/3

So you were right. 18 for the twins and 6 for Emily.

Problem two: there isn't enough info to tell how many Katy got right, but I can te u how many were on the teast.
X=number of 2 point problems
Y=number of three point problem

Equation 1:
2x+3y=100
Equation 2:
X+y=42

If you substitute just like last time:

X+y=42 so y=42-x

The variable cross each other out and:

42=42

The answer J's I.finite number of solutions.
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