Solve this system
[ y=x^2-3x-8
[ y= x + 4
Im not looking for the answer, as I already have it, I need to understand the concept of HOW to do this type of problem.
*The answer should be in coordinate form.
[ y=x^2-3x-8
[ y= x + 4
Im not looking for the answer, as I already have it, I need to understand the concept of HOW to do this type of problem.
*The answer should be in coordinate form.
-
Basically, you take one equation and plug it into the other. So if you take the second equation and plug it in for every "y" in the first one, you get x+4=x^2-3x-8
Then you solve for x.
Finally, take the value of x and plug it into your original second equation to find the value of y.
Then you solve for x.
Finally, take the value of x and plug it into your original second equation to find the value of y.