Challenging math problem anyone
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Challenging math problem anyone

[From: ] [author: ] [Date: 12-01-13] [Hit: ]
............
Robert Jones.............f
"Teacher/Tutor of Fine Students"

A PRESENT FOR YOU

Ask someone to write a number, say a five-digit number.
(Can be a 2-digit.....3-digit.....4-digit....ect..…
Suppose the number written is
57836

Now, without showing the asker, you write a number on
a sheet of paper and keep it folded. You have to write the
number by subtracting 2 from the above number and
adding 2 in front which will be....
257834

Next, ask the person to write another five-digit number
below his original number. Suppose he writes 37589.
So you now have...

57836
37589

Now you write a five-digit number below it in such a
way that each digit is 9 minus digit above. You now have...

57836
37589
62410

Ask the person to add one more 5-digit number. If he
adds 54732, you add below it 45267. Note that you decided
the number by subtracting each of his digit from 9.
Thus, you now have.....

57836
37589
62410
54732
45267

Next, ask him to add all the number and he gets 257834

Show him the number which you had written as an answer
to this addition earlier in the folded paper and surprise him.

-
(A) So after 0 months, she would have 650 (this is your "y-intercept." She adds 30 per month (this is your "slope"). So the function is f(m) = 30m + 650

(B) 1 year = 12 months, meaning m = 12. Putting this into the f(m) formed above,
f(12) = 30*12 + 650 = 1010 pennies

(C) f(m) must equal 5000
f(m) = 30m + 650 = 5000
30m = 4350
m = 145 months = 12 years, 1 month

(D) Assuming she still collects 30 coins, the equation would be f(m) = 30m + 40, which we want to equal "d"
30m + 40 = d
30m = d - 40
m = (d - 40)/30

-
a) Slope is 30 and y-intercept is 650 so the equation is F(m)=30m+650

b) By plugging in one year or 12 moths into the equation we get 30*12+650=1010

c) Set the equation equal to 5000:

5000=30m+650
4350=30m
145=m

To change that to years just divide months by 12. 145/12=12.083 years

d) If a= the amount added each month, d=am+40

d-40=am
(d-40)/a=m

-
f(m) = 30m + 650
f(12) = 1010
m = (5000 - 650)/30 = 145 months = 12 years 1 month

how many dimes per month does Tara save? let's call it T. I won't assume it's 3 dimes (which is the same amount of money as 30 pennies)
when Tm+40=d, jar is full. so m=(d-40)/T
12
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