A little confused, if you could explain how you got the answer that would be great!
Thanks
Thanks
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4x+5y=11
4x+5y=10
4x+5y=13
4x=0.12-5y
2.5y=-2x+65
1=(14-5y)/4x
Any of these work. Pretty much, all you need to do is change the vertical intercept, or the constant.
4x+5y=10
4x+5y=13
4x=0.12-5y
2.5y=-2x+65
1=(14-5y)/4x
Any of these work. Pretty much, all you need to do is change the vertical intercept, or the constant.
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The standard form of the line is y = [- 4x + 12]/5 = -(4/5)x + 12/5
The y-intercept = 12/5. A parallel line must have the same slope (-4/5) but can
have any other y-intercept, such as 0. Then y = -(4/5)x, i.e., {4x + 5y = 0} is
one example, as is y = -(4/5)x + 100, i.e., {4x + 5y = 500} and an infinity
of others.
The y-intercept = 12/5. A parallel line must have the same slope (-4/5) but can
have any other y-intercept, such as 0. Then y = -(4/5)x, i.e., {4x + 5y = 0} is
one example, as is y = -(4/5)x + 100, i.e., {4x + 5y = 500} and an infinity
of others.
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equation of a line that would be parallel to:4x + 5y = 12 is
4x + 5y = k ANSWER where k is decided by other conditions.
4x + 5y = k ANSWER where k is decided by other conditions.
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11x+18y=17