Geometry slope question

Please please explain how I can do these,
I really appreciate it because I don't understand this at all!
1. Write an equation of a line in slope intercept form that is parallel to the line x + 4y = 6 and passes through (-8, 5).
2. Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).

Thank you!

1)Find the slope of the line x + 4y = 6

4y=-x+6

y=(-1/4)x+3/2 the slope =-1/4

The other line's slope=-1/4

y-y1=m(x-x1)

y-5=(-1/4)(x+8)

y-5=(-1/4)x-2 add 5 to each side

y=(-1/4)x+3


2) Find the slope of 2x -3y = 12

-3y=-2x+12 divide both sides by -3

y=(2/3)x - 4

The slope of the other line is -3/2

y-y1=m(x-x1)

y-6=(-3/2)(x-2)

y-6=(-3/2)x+3 add 6 to each side

y=(-3/2)x+9