How do I find the imaginary part of this function
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How do I find the imaginary part of this function

[From: ] [author: ] [Date: 11-12-15] [Hit: ]
-Multiply both the numerator and denominator by the complex conjugate of the denominator - in this case ((x²- y²) - 2ixy).This will leave you with no complex terms in the denominator and you will be able to separate terms.......
I need to write this function as f(x,y) = u(x,y) + iv(x,y), but I can't figure out how to break it up into purely real and purely imaginary parts.

f = i * Im(z) / z²

If z = x + iy
i * Im(z) = iy
z² = (x + iy)² = x² + 2ixy - y²

So f = iy / (x² + 2ixy - y²)

And that's where I get stuck...

-
Multiply both the numerator and denominator by the complex conjugate of the denominator - in this case ((x² - y²) - 2ixy). This will leave you with no complex terms in the denominator and you will be able to separate terms.
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