Show that : d(e+logx^e)={e/x.log^(e-x)(x)}dx

I am not sure, What you want to prove : However,

d(e+logx^e)={e/x.log^(e-x)(x)}dx

=>d/dx(e+logx^e)={e/x.log^(e-x)(x)}

do you want to prove this ?

Prove: L.H.S

= d/dx(e+logx^e)

= d/dx(e)+d/dx(logx^e) [d/dx(e)=0]

= 0+ e.log^(e-x)(x)(d/dx(logx))

= e.log^(e-x)(x).(1/x)

=e/x.log^(e-x)(x)

=R.H.S

What is the meaning of log^(e - x)(x) ? Clarify