Condensing Logarithmic expressions

how would you condense this into one logarithm?

3(logx^2 - logy) - (log 4 + 2log 5x)

the 4 and 5x are not bases in the seconde part fyi.
If anyone could help me understand this for my test tom i would be glad thanks

Generally,
logx - logy = log(x/y)
logx + logy = log(xy)
xlogy = log(y^x)

3(logx^2 - logy) - (log4 + 2log(5x)) =
3(log(x^2/y)) - (log4 + log((5x)^2)) =
log((x^2/y)^3) - log(4(25x^2)) =
log(x^6/y^3) - log(100x^2) =
log(x^6/(100x^2y^3)) =
log(x^4/(100y^3))

3(logx^2 - logy) - (log 4 + 2log 5x)
=3(log(x^2/y) - (log 4 + (log 5x)^2
=log{(x^2/y)^3} - log {(4)*(5x)^2}
=log{(x^2/y)^3 / (4)*(5x)^2}
=log{(x^2/y)^3 / 100(x)^2}
=log{(x^2/y)^3 / 100(x)^2}