can somebody help me isolate X in the following equation:
100^2 = y^2 + x^2 - 2xy(cos 65)
all i need is for X to be isolated on oneside of the equal sign. I have realized the the
x^2 + 2xy(cos 65) + y^2 kinda looks like x^2+2xy+y^2. but i dont know what to do with the information.
thanks. :)
100^2 = y^2 + x^2 - 2xy(cos 65)
all i need is for X to be isolated on oneside of the equal sign. I have realized the the
x^2 + 2xy(cos 65) + y^2 kinda looks like x^2+2xy+y^2. but i dont know what to do with the information.
thanks. :)
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That equation represents an ellipse with its centre at the origin, sloping upwards from left to right at 45°, and intercepting each axis at ±100. Every point (x, y) on the ellipse is a solution to the equation, so you need some other condition if you are trying to identify specific points.
Otherwise I doubt whether separating the variables is possible, or would make much difference. It might help if you could outline what you are trying to do here.
Otherwise I doubt whether separating the variables is possible, or would make much difference. It might help if you could outline what you are trying to do here.
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This is a bit messy, but you could arrange it as x^2 - 2xy(cos 65) + y^2 - 100^2 = 0
and then use the quadratic formula to find x.
and then use the quadratic formula to find x.
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as you like
100^2 = y^2 + x^2 - 2xy(cos 65)
100^2=x^2-2xy(cos 65)+y^2=
x^2-2xy(cos 65)+(ycos65)^2-(ycos65)^2+y^2
(x-ycos65)^2+(y^2)(1-(cos65)^2=100^2
(x-ycos65)^2=-(y^2)(1-(cos65)^2+100^2
(x-ycos65)^2=-(y^2)(sin65)^2+100^2
hope it will help
100^2 = y^2 + x^2 - 2xy(cos 65)
100^2=x^2-2xy(cos 65)+y^2=
x^2-2xy(cos 65)+(ycos65)^2-(ycos65)^2+y^2
(x-ycos65)^2+(y^2)(1-(cos65)^2=100^2
(x-ycos65)^2=-(y^2)(1-(cos65)^2+100^2
(x-ycos65)^2=-(y^2)(sin65)^2+100^2
hope it will help