Frances left a 19% tip on a meal. Including the tip, its cost was $40.46. What was the cost of the meal before the tip?
Here is what I did :
Supposedly, x : the total cost ($40.46) ; y : the tip [ 19% ( $40.46)] ; z : the cost of the meal.
=> x = y + z <=> 40.46 = 19% x ( 40.46) + z
<=> z = 40.46 - 7.6874
<=> z = 32.7726
=> The cost of the meal before the tip was $32.7726
=> MathXL said that answer was wrong ?
What's wrong ?
Thanks in advance guys !
Here is what I did :
Supposedly, x : the total cost ($40.46) ; y : the tip [ 19% ( $40.46)] ; z : the cost of the meal.
=> x = y + z <=> 40.46 = 19% x ( 40.46) + z
<=> z = 40.46 - 7.6874
<=> z = 32.7726
=> The cost of the meal before the tip was $32.7726
=> MathXL said that answer was wrong ?
What's wrong ?
Thanks in advance guys !
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The meal plus tip was $40.46.
i.e. 100% of the meal plus the tip which was 19% of meal totaled $40.46.
i.e. 119% of the meal was $40.46.
So, If we let x represent the cost of the meal before the tip,
then 119%x = $40.46
1.19x = $40.46
x = $40.46/1.19
x = $34
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The meal plus tip was $40.46.
i.e. 100% of the meal plus the tip which was 19% of meal totaled $40.46.
i.e. 119% of the meal was $40.46.
So, If we let x represent the cost of the meal before the tip,
then 119%x = $40.46
1.19x = $40.46
x = $40.46/1.19
x = $34
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No it should be 34.
Let the meal cost before the tip be x.
Then x + 0.19x = 40.46.
Solve for x: x = 34.
Let the meal cost before the tip be x.
Then x + 0.19x = 40.46.
Solve for x: x = 34.