7x + 6 = -5x + 10
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12x = 4
x = 1/3
x = 1/3
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7x+6=-5x+10 first get x's on same side of equation by additing 5x to both sides
7x+5x+6=-5x+5x+10 combine the x's
12x + 6 = 10 now subtract 6 from both sides
12x = 4 solve for x by dividing both sides by 12
x = 4/12 4/12 reduces to 1/3 so x=1/3
7x+5x+6=-5x+5x+10 combine the x's
12x + 6 = 10 now subtract 6 from both sides
12x = 4 solve for x by dividing both sides by 12
x = 4/12 4/12 reduces to 1/3 so x=1/3
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Whatever you do to one side, you must do to another, so:
7x+6=-5x+10 (First, add 5x to both sides)
12x+6 = 10 (Then subtract 6)
12x = 4 (Finally, divide by 12)
x= 1/3
7x+6=-5x+10 (First, add 5x to both sides)
12x+6 = 10 (Then subtract 6)
12x = 4 (Finally, divide by 12)
x= 1/3
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7x + 6 = -5x + 10
7x = -5x + 4 {subtracted 6 from both sides}
12x = 4 {added 5x to both sides}
x = 4/12 {divided both sides by 12}
x = 1/3 {reduced}
http://www.algebrahouse.com
7x = -5x + 4 {subtracted 6 from both sides}
12x = 4 {added 5x to both sides}
x = 4/12 {divided both sides by 12}
x = 1/3 {reduced}
http://www.algebrahouse.com
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i take it ur solving for x?
get the x's on both sides. add 5 to 7. if the 5 was positive it would be minus 5.
Now it looks like this. 12x + 6 = 10 lose the 6. so -6 to 10.
Now its 12x=4
Divide by 4
X= 0.33333333333
get the x's on both sides. add 5 to 7. if the 5 was positive it would be minus 5.
Now it looks like this. 12x + 6 = 10 lose the 6. so -6 to 10.
Now its 12x=4
Divide by 4
X= 0.33333333333
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put common stuff on 1 side. 12X=+10-6=4 so 12 X=4 X=1/3. checking 7+18= -5 +30 or 25=25. See?
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7x + 6 = -5x + 10
7x + 5x = 10 - 6
12x = 4
x = 4/12
x = 1/3 Ans
7x + 5x = 10 - 6
12x = 4
x = 4/12
x = 1/3 Ans
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7x + 6 = -5x + 10
12x = 4
x = 4 / 12 = 1 / 3
12x = 4
x = 4 / 12 = 1 / 3
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7x + 6 = -5x + 10
12x + 6 = 10
12x=4
x=4/12
x=1/3
12x + 6 = 10
12x=4
x=4/12
x=1/3
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7x + 6 = -5x + 10
7x+5x=4
12x=4
x=4/12
x=1/3
7x+5x=4
12x=4
x=4/12
x=1/3
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12x=4
=>x=1/3
=>x=1/3
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12x=4
x=1/3
x=1/3
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X=2
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X=1/3
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x=1/3
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.33sub 6 then add 5 then do 4/12
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Solve for X.