Maths help desperately needed
[From: ] [author: ] [Date: 11-05-12] [Hit: ]
divide both sides by three you get 3x/3=9/3. So 3/3=1 and 9/3=1, thus you get your answer x=3. For the second question, if they require you to solve it using algebraic identity, do the following steps:1.......
then 3 = 3 and it makes sense.
But if I only do it to one side and let 3 + 4 = 3, then it doesn't make sense.
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You need to imagine x as a solution you do not know. And in algebraic equations, there are rules you MUST memorise before taking any tests. For example, you need to know when you can bring values over to the other side, be it adding, subtracting, multiplying or dividing. For inequalities, you need to know that the sign (< , >) will change when the expression is multiplied by -1. For 3x=9, divide both sides by three you get 3x/3=9/3. So 3/3=1 and 9/3=1, thus you get your answer x=3. For the second question, if they require you to solve it using algebraic identity, do the following steps:
1. Let x units^2 be the area of the circle (I presume)
2. Form an equation: x=pi * 3^2
3. Solve the equation: x=9 * pi
Depending on what pi is, sub the value times 9.
x= 28.3 (3 significant figures)
4. Therefore, area of circle is 28.3 (3sf) units^2.
I really hope this helps. Do your best!
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3x=9
3/3x=9/3 what i did here was to divide so x would stand alone aka 3/3=1 i will also do this on the other side or else it would make no sense 1x=3
x=3
Area=3,14*3*3(type this into a calculator and hit the "=", then hit the √
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I don't know the answer sorry but what I do know is I really don't think studying maths at uni is a good idea considering your on your 3rd attempt to even pass a maths exam.
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1. X=9/3=3
2. Area=pie*3^2=28.27sq. Unit
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